What's wrong with this C++ program?

#include %26lt;iostream%26gt;





using namespace std;





int main(int argc, char *argv)


{


cout %26lt;%26lt; "This will contain numbers 1-10:\n";





for(int i = 1; %26lt;= 10; i++)


cout %26lt;%26lt; i %26lt;%26lt; endl;





return 0;


}

What's wrong with this C++ program?
The only critical error is in the syntax of the


termination condition of the "for" loop. There's


a typo such that it only says:





    %26lt;= 10





and it should be:





    i %26lt;= 10





There's a technical (but in this case unimportant)


error in that the prototype for "main" should be:





    int main(int argc, char* argv[])





Note that the second parameter is not a pointer


to char, but rather a pointer to array of char.





The repaired code looks like:








#include %26lt;iostream%26gt;





using namespace std;





int main(int argc, char *argv[])


{


   cout %26lt;%26lt; "This will contain numbers 1-10:\n";





   for(int i = 1; i%26lt;= 10; i++)


     cout %26lt;%26lt; i %26lt;%26lt; endl;





   return 0;


}
Reply:where it says ''argc'' it should say ''arge''
Reply:You're missing the "i" before expression "%26lt;=10"





corrected:


for(int i = 1; i %26lt;= 10; i++)

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