C++ error!!!!?

this program get the size if an array , i want to fix the error


#include%26lt;iostream%26gt;


using namespace std;


int main()


{


int arr[5]={1,2,3,4,5};


int * begin,*end;


begin=arr[0];


end=arr[5];


return begin-end-1;


system("pause");


return 0;


}

C++ error!!!!?
There are a few problems here.





arr[0] = the contents of the first element of the array, not its address. You need to set begin to either arr, or %26amp;arr[0].





arr[5] indexes outside the bounds of the array. I can't tell you what its value is, but you shouldn't be referencing there. Set end to %26amp;arr[4].





The address of the beginning of the array is less than the address of second, and subsequent, elements of the array. So your statement: begin - end - 1, will be a negative value.





I guess you want to use pointers, or array addresses, to compute the size. Your code should look something like this:





#include %26lt;iostream%26gt;





using namespace std;





int size(int *begin, int *end);





int main(int argc, char *argv[]) {


int a[] = {1,2,3,4,5};


int len = sizeof(a) / sizeof(*a);





cout %26lt;%26lt; "num elements in a = " %26lt;%26lt; len %26lt;%26lt; endl;


cout %26lt;%26lt; "size(a) = " %26lt;%26lt; size(a,%26amp;a[len-1]) %26lt;%26lt; endl;


}





int size(int *begin, int *end) {


return end - begin + 1;


}
Reply:This program doesn't make any sense. What have you been trying to achieve ?





The size of the array in elements is calculated as


sizeof(arr)/sizeof(int).





If you wanted address of the first and last elements, it would be %26amp;arr[0] and %26amp;arr[4] (not 5).





system("pause") will not be executed because you terminate the program by "return" before that.

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