Converting a vector of ints into binary in C++?

I'm trying to write a program that converts a string to a vector of ints to binary to hexadecimal. The reason it's started off as a string instead of an int is because an int has a limit, so the string is supposed to work for any huge number.





So far I have converted a string to a vector of ints. But now I'm not really sure how to convert a vector to a binary number.





I have:





#include%26lt;iostream%26gt;


#include%26lt;vector%26gt;


#include%26lt;string%26gt;





using namespace std;





int main(void)





{





cout%26lt;%26lt;"Type in a string: ";


string s;


cin%26gt;%26gt;s;





// converting the string to a vector





vector%26lt;int%26gt;v;


for (int i = 0; i %26lt; s.length(); i = i + 1)


{


v.push_back(s[i]-48);


}





// printing out the vector


cout%26lt;%26lt;"vector v is: ";


for (int i = 0; i %26lt; v.size(); i = i + 1)


{


cout%26lt;%26lt;v[i];


} cout%26lt;%26lt;endl;














return 0;


}





Any help would be great, thanks!

Converting a vector of ints into binary in C++?
/* outline the program */





// void main()...etc..





/* define your variables */


/* you'll need a pair of char pointers */


/* and some numbers to hold converted values */








/* input the first binary as a string */





/* input the second binary as a string */





/* convert them to decimal */





/* add them */





/* fprintf them */





/* end program */





or





You can use a look-up table for the characters 0 to 9 and A to F


0 = 0000


1 = 0001


2 = 0010


...


D = 1101


E = 1110


F = 1111


Split your hex value into each character, get the corresponding binary value as a string, concatenate the strings together in the same order.