#include %26lt;iostream%26gt;
using namespace std;
void main ()
{//begin main
//declare and initialize
int counter = 1;
int counter2 = 1;
int counter3 = 1;
//Process and Output
//For Loop: //test before
{
for(counter = 1; counter %26lt;= 10; counter++);
cout %26lt;%26lt; "Loop counter is at " %26lt;%26lt; counter %26lt;%26lt; endl;
counter = counter +1;
}
//While Do Loop: //test before
while (counter2 %26lt;= 10)
{
cout %26lt;%26lt; "Loop counter2 is at " %26lt;%26lt; counter2 %26lt;%26lt; endl;
counter2 = counter2 +1;
}
//Do While loop: //test after
do
{//begin loop
cout %26lt;%26lt; "Loop counter3 is at " %26lt;%26lt; counter3 %26lt;%26lt; endl;
counter3 = counter3 +1;
}//end loop
while (counter3 %26lt;= 10);
}
How do I do a for loop in C++ that will give me an output of 1-2-3-4-5-6-7-8-9-10. Mine is only giving me 10.?
In addition to the extra semi-colon (;), you are incrementing counter twice, so the output would be 1, 3, 5, 7, 9 for the for loop.
for(counter = 1; counter %26lt;= 10; counter++);
cout %26lt;%26lt; "Loop counter is at " %26lt;%26lt; counter %26lt;%26lt; endl;
counter = counter +1;
}
Should be
for(counter = 1; counter %26lt;= 10; counter++)
{
cout %26lt;%26lt; "Loop counter is at " %26lt;%26lt; counter %26lt;%26lt; endl;
}
Or
for(counter = 1; counter %26lt;= 10;)
{
cout %26lt;%26lt; "Loop counter is at " %26lt;%26lt; counter %26lt;%26lt; endl;
counter = counter +1;
}
Also, I would recommend getting in the habit of using counter++; instead of counter = counter + 1;
It looks better and is more efficient.
Reply:for(counter = 1; counter %26lt;= 10; counter++);
Is your culprit. By having the ; at the end. the loop does nothing. Remove the ; and the body of the loop will be run correctly.
Enjoy!
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