C++ Palindrome Number?

#include "stdafx.h"


#include %26lt;iostream%26gt;


#include %26lt;cmath%26gt;





using namespace std;





bool isNumPalindrome (int num);








int main()


{


//I dont know what to input here


return 0;


}





bool isNumPalindrome (int num)


{


double pwr = 0;





//Step 1


if (num %26lt; 10)


return true;


//Step 2


else


{


// Step 2.a


while (num / static_cast%26lt;int%26gt;(pow(10,pwr)) %26gt;= 10)


pwr++;


while (num %26gt;=10) //Step 2.b


{


int tenTopwr = static_cast%26lt;int%26gt; (pow(10,pwr));





if ((num / tenTopwr) != (num % 10))


return false; //Step 2.b.1


else //Step 2.b.2


{


num = num % tenTopwr; //Step 2.b.2.1


num = num /10; //Step 2.b.2.1


pwr = pwr -2; //Step 2.b.2.2


}


}//end while


return true;


}//end else


return 0;


}











I dont know how to call the isnumpalindome in the int main()

C++ Palindrome Number?
int main()


{


for (int i=0; i%26lt;40000000; ++i)


if (isNumPalindrome(i)) // called here


printf("This is a Palindrome\n");


else


printf("This is not a Palindrome\n");


return 0;


}